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Now this probability is the absolute square of an amplitude, and if the absolute square is zero, the amplitude is also zero, so that we have a wave train whose length is $\Delta x$ (Fig. 2–1 ), and the wavelength (the distance between nodes of the waves in the train) of that wave train is what corresponds to the particle momentum. This is due to the factor of γ ≡ (1 − v 2 /c2 )−1/2 in the relativistic definition of momentum, p = mvγ, which means that dmx = p (relativistic case). (11.15) dt So far we have put no restrictions on the movements of the two particles.

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Publisher: Cambridge University Press (August 5, 2012)

ISBN: 0511622643

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