Download Joe Celko's SQL Puzzles and Answers: The Morgan Kaufmann in by Joe Celko PDF
By Joe Celko
During this whole revision and growth of his first SQL Puzzles e-book, Joe Celko demanding situations you together with his trickiest puzzles—and then is helping resolve them with a number of ideas and reasons. Joe demonstrates the idea procedures which are fascinated by attacking an issue from an SQL point of view to aid complicated database programmers resolve the puzzles you regularly face. those recommendations not just support with the puzzle handy, yet support increase the attitude had to remedy the numerous tough SQL puzzles you face on a daily basis. after all, a part of the joys is to determine even if you could write greater ideas than Joe’s.
* an outstanding choice of tough SQL puzzles with quite a few options and factors.
* makes use of the confirmed structure of puzzles and suggestions to supply a straightforward, useful inspect SQL programming difficulties - lots of as a way to support clients remedy their very own difficulties.
* re-creation beneficial properties:
— Many new puzzles added!
— Dozens of recent suggestions to puzzles, and utilizing good points in SQL-99
— Code is edited to comply to SQL type rules
— New bankruptcy on temporal question puzzles
— New bankruptcy on universal misconceptions approximately SQL and RDBMS that ends up in difficulties
Read or Download Joe Celko's SQL Puzzles and Answers: The Morgan Kaufmann in Data Management Systems (2nd Edition) PDF
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Additional info for Joe Celko's SQL Puzzles and Answers: The Morgan Kaufmann in Data Management Systems (2nd Edition)
Departure_date))); 22 PUZZLE 6 HOTEL RESERVATIONS Answer #2 Another solution is to redesign the table, giving a row for each day and each room, thus: CREATE TABLE Hotel (room_nbr INTEGER NOT NULL, occupy_date DATE NOT NULL, guest_name CHAR(30) NOT NULL, PRIMARY KEY (room_nbr, occupy_date, guest_name)); This does not need any check clauses, but it can take up disk space and add some redundancy. Given cheap storage today, this might not be a problem, but redundancy always is. You will also need to find a way in the INSERT statements to be sure that you put in all the room days without any gaps.
You could drop that PUZZLE 4 SECURITY BADGES 17 CHECK() clause and allow an employee to have no active badge. That, however, would mean that you have to create a way of updating the badge status of the most recently issued badge to “A” for the employees. emp_id)); Again, I must point out that a lot of SQL implementations will also gag on this update because of the correlation names. The rule in SQL-92 is that the scope of the table name in the UPDATE is the whole statement, and the current row is used for the column values referenced.
You want to produce a list of personnel and their active security badge numbers. Each employee can have many badges, depending on how many job sites they are currently working, but only one of their badges will be active at a time. The default is that the most recently issued badge is assumed to be active because it will be issued at a new job site. The badge numbers are random to prevent counterfeiting. Your task is to produce a list of personnel, each with the relevant active badge number. Let’s use ‘A’ for active and ‘I’ for inactive badge status.